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Luigi Paura » 7.Error probability for M-PSK


Error probability for M-PSK


Error probability for M-PSK (next)


Demodulation for bandpass signals


Synchronization


Differential PSK

If the phase is:

ø’=ø+π→2ø’=2ø’+2π=2ø’mod2π

therefore there is a π ambiguity in the phase estimate

Such ambiguity destroys the information which is carried by a phase of “0″ or “π”

Differential PSK (next)

If the information is carried by the phase difference associated with two adiacent symbols rather than the phase associated with a single symbol the ambiguity is removed.


Differential PSK (next)

By means of a differential coding the ambiguity problem has been solved.
Both the differential coding and decoding are implemented by simple logic circuits which precede the modulator and follow the detector, respectively.


Non-coherent demodulation for differential PSK


Non-coherent demodulation for differential PSK (next)


Error probability for differential B-PSK (D-BPSK)

If a coherent receiver is utilized, the P(e) is roughly double the P(e) obtained with the B-PSK (non differential).
This result is justified by considering that if a symbol interval is highly corrupted by noise, such an event can cause two errors in two consecutive decisions.
If a non-coherent receiver is utilized which performs the decisions by resorting to rn (rn-1)*, it can be shown that the decision variable can be approximated with the one associated with the coherent receiver provided that the noise component exhibits a double power → 3dB loss in SNR (OK for M > 4).

Error probability for differential B-PSK (D-BPSK)  (next)


Error Probability for QAM


Comparison between QAM and M-PSK


Union Bound


Union Bound (next)


Union Bound (next)


Union Bound


Comparison between the memoryless modulation schemes (MMS)

The MMScan be compared in several ways. For example:
Which is the required ratio Eb/N0 to assure a given Pb for a fixed channel bandwidth 2W (or bit rate Rb) ?
Which is the minimum channel bandwidth ( or the maximum Rb ) to obtain a given Pb for a fixed Eb/N0

Comparison between the memoryless modulation schemes (MMS) (next)

How to evaluate the bandwidth of a modulation scheme?
The Shannon bandwidth gives a measure of the spectral occupacy without requiring the knowledge of the specific signal waveform.


Comparison between the memoryless modulation schemes (MMS) (next)


Comparison between the memoryless modulation schemes (MMS) (next)


Comparison between the memoryless modulation schemes (MS)


Comparison between the memoryless modulation schemes (MS) (next)


Comparison between the memoryless modulation schemes (MS) (next)

Efficient in power:
The PAM signals present a Pb which increases with M increasing (or k) for a fixed Eb/N0
To mantain Pb constant it is necessary to increase Eb/N0
The PAM signals are not efficient in power.
Analogously for M-PSK and QAM
The orthogonal signals exhibit a Pb which decreases with M (with k)
Analogously for simplex signals as well as biorthogonal ones

Comparison between the memoryless modulation schemes (MS) (next)


Coded Transmissions

Do signaling schemes exist which are both efficient in power and in bandwidth?
Yes


Comparison between the memoryless modulation schemes (MS)

How do we pay the bandwidth and/or power saving?
We pay with the complexity increasing in transmission (coder) and in reception (decoder)

Comparison between the memoryless modulation schemes (MS) (next)


Comparison between the memoryless modulation schemes (MS) (next)

The comparison must take into account also the complexity of the devices in transmission and in reception.
Example:
The PAM signals require a single correlator.
The orthogonal signals require (in general) M correlators

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